Tangents `PT_1, and PT_2`, are drawn from a point P to the circle `x^2 +y^2=a^2`. If the point P line `Px +qy + r = 0`, then the locus of the centre of circumcircle of the triangle `PT_1T_2` is

Tangents PT_1, and PT_2 , are drawn from a point P to the circle x^2 +y^2=a^2 . If the point P lies on the line Px +qy + r = 0 , then the locus of the centre of circumcircle of the triangle PT_1T_2 is

Tangents PT_1, and PT_2 , are drawn from a point P to the circle x^2 +y^2=a^2 . If the point P lies on the line Px +qy + r = 0 , then the locus of the centre of circumcircle of the triangle PT_1T_2 is

Tangents PT_(1), and PT_(2) are drawn from a point P to the circle x^(2)+y^(2)=a^(2). If the point P line Px+qy+r=0 ,then the locus of the centre of circumcircle of the triangle PT_(1)T_(2) is

A pair of tangents are drawn from a point P to the circle x^2+y^2=1 . If the tangents make an intercept of 2 on the line x=1 then the locus of P is

Tangents PA and PB are drawn from a point P to the circle x^(2)+y^(2)-2x-2y+1=0. If the point plies on the line lx+my+n=0 , where l,m,n are constants,then find the locus of the circum-Centre of the Delta PAB.

Tangents drawn from the point P (1, 8) to the circle x^2+ y^2 - 6x - 4y - 11 = 0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is:

A pair of tangents are drawn from a point P to the circle x^(2)+y^(2)=1. If the tangents make an intercept of 2 on the line x=1 then the locus of P is

Tangents drawn from the point P(1,8) to the circle x^(2) + y^(2) - 6x - 4y -11=0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is:

Tangents PA and PB are drawn to the circle (x+3)^(2)+(y-4)^(2)=1 from a variable point P on y=sin x. Find the locus of the centre of the circle circumscribing triangle PAB.