In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that:
` AB^(2)-BD^(2)= AC^(2)-CD^(2)`

In ABC,AD is perpendicular to BC. Prove that: AB^(2)+CD^(2)=AC^(2)+BD^(2)( ii) AB^(2)-BD^(2)=AC^(2)-CD^(2)

In Delta ABC, AD_|_ BC . Prove that AB^(2) - BD^(2) =AC^(2) -CD^(2)

In triangle ABC, AB=AC and BD is perpendicular to AC. Prove that : BD^(2)-CD^(2)=2CDxxAD

ABC is a right angled triangle right angled at C. CD is perpendicular on the hypotenuse AB. Prove that (BC^2)/(AC^2)=(DB)/(AD) .

ABC is a right-angled triangled, right angled at A*AD is drawn perpendicular to BC from A . Then AB^2 is equal to

ABC is a right triangle , right angled at A and D is the mid point of AB . Prove that BC^(2) =CD^2 +3BD^(2) .

ABC is a right angled triangle right angled at C. CD is perpendicular on the hypotenuse AB. Prove that (AC^2)/(BC^2)=(AD)/(DB)

ABC is a right angled triangle right angled at C. CD is perpendicular on the hypotenuse AB. Prove that (BC^2)/(CD^2)=(AB)/(AD)

In DeltaABC , AD is drawn perpendicular to BC. If BD:CD=3:1 , then prove that BC^(2)=2(AB^(2)-AC^(2)) .

In an isosceles triangle ABC with AB = AC, BD is perpendicular from B to side AC. Prove that BD^(2)-CD^(2)=2CD.AD