Home
Class 11
MATHS
Let S be the focus of the parabola y^2=8...

Let S be the focus of the parabola `y^2=8x` and let PQ be the common chord of the circle `x^2+y^2-2x-4y=0` and the given parabola. The area of the triangle PQS is -

Text Solution

Verified by Experts

`y^2=8x`
`y^2=4ax`
4a=8
a=2
`P(at^2,2at)->P(2t^2,4t)`
`4t^4+16t^2-4t^2-16t=0`
`4t(t^3+3t-4)=0`
t=0,1.
...
Promotional Banner

Similar Questions

Explore conceptually related problems

Let S be the focus of the parabola y^2=8x and let PQ be the common chord of the circle x^2+y^2-2x-4y=0 and the given parabola. The area of the triangleQPS is

The focus of the parabola x^2-8x+2y+7=0 is

The focus of the parabola x^2-8x+2y+7=0 is

The focus of the parabola x^2-8x+2y+7=0 is

The focus of the parabola x^2-8x+2y+7=0 is

The focus of the parabola y^(2)-4y-8x-4=0 is

The focus of the parabola y^(2)-4y-8x-4=0 is

The focus of the parabola y^(2) -8x-2y+2 = 0 is

The focus of the parabola y^(2)-4y-8x+4=0 is,