Two capacitors of `3 pF` and `6pF` are connected in series and a potential difference of `5000 V` is applied across the combination. They are then disconnected and reconnected in parallel. The potential between the plates is

Two capacitors of 3muF and 6 muF are connected in series and a potential difference of 900 V is applied across the combination. They are then disconnected and reconnected in parallel. The potential difference across the combination is

Two capacitors of 3muF and 6muF are connected in series and a potential difference of 900 V is applied across the combination. They are then disconnected and reconnected in parallel. The potential difference across the combination is

Three capacitors of capacitance 1 muF, 2muF and 3 muF are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 muF capacitor is

The capacitances of two capacitors are 2 mu F and 8 mu F . They are connected in series and a potential difference of 100 V is applied across the combination. What are The potential differences across the two capacitors?

Two capacitors 3muF and 6muF are connected in series across a potential difference of 120V . Then the potential difference across 3muF capacitor is:

Two capacitors of capacitance C_(1) and C_(2) are connected in parallel and a charge Q is delivered to the combination. The two are then disconnected and reconnected in series. What are the new potential differences and charge on the capacitors?