If`D=d i ag[d_1, d_2, d_n]` , then prove that `f(D)=d i ag[f(d_1),f(d_2), ,f(d_n)],w h e r ef(x)` is a polynomial with scalar coefficient.

If D=diag[d_(1),d_(2),...d_(n)], then prove that f(D)=diag[f(d_(1)),f(d_(2)),...,f(d_(n))], where f(x) is a polynomial with scalar coefficient.

Let R be a relation such that R={(a d) (c g) (d e) (d f) (g f)} then (ROR^(1))^(-1) is

Find sum f_(i)d_(i) , if bar(d) = 1.2 and sum f_(i) = 25 .

Let D_1=|a b a+b c d c+d a b a-b|a n dD_2=|a c a+c b d b+d a c a+b+c| then the value of |(D_1)/(D_2)|,w h e r eb!=0a n da d!=b c , is _____.

Let D_1=|a b a+b c d c+d a b a-b|a n dD_2=|a c a+c b d b+d a c a+b+c| then the value of |(D_1)/(D_2)|,w h e r eb!=0a n da d!=b c , is _____.

Let D_1=|a b a+b c d c+d a b a-b|a n dD_2=|a c a+c b d b+d a c a+b+c| then the value of |(D_1)/(D_2)|,w h e r eb!=0a n da d!=b c , is _____.

Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D^*F(x) by the formula D*f(x)=lim_(h->0)(f^2(x+h)-f^2(x))/h ,w h e r ef^2(x) mean [f(x)]^2 and if f(x)=xlogx ,then D^*f(x)|_(x=e) has the value (A)e (B) 2e (c) 4e (d) none of these

Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D^*F(x) by the formula D*f(x)=lim_(h->0)(f^2(x+h)-f^2(x))/h ,w h e r ef^2(x) mean [f(x)]^2 and if f(x)=xlogx ,then D^*f(x)|_(x=e) has the value (A)e (B) 2e (c) 4e (d) none of these