Find the points of the xaxis, whose distances from the line `x/3+y/4=1`are 4 unit is.

Explanation

The given equation of line is 4x+3y−12=0.


Let (a,0) be the point on the x-axis whose distance from the given line is 4 units.


Thus, using distance formula,
`4= | quad (4a-12)| div (sqrt(4^2+3^2))`


`|quad ( 4a-12)| =20`
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