In a given figure in trapezium `ABCD if AB || CD` then value of `x` is :

In a given figure in trapezium ABCD if AB| | CD then value of x is :

In figure, AB ||CD, the value of x is

In the given figure AB || CD, BC || DE then find the values of x and y

In the given figure AB || CD, BC || DE then find the values of x and y

In the given figure AB || CD, BC || DE then find the values of x and y

In the given figure AB || CD, BC || DE then find the values of x and y

In the given figure AB || CD, BC || DE then find the values of x and y

In the given figure ABCD is a trapezium with AB || DC. E and F are respectively midpoint of AD and BC. Prove that, EF=1/(2)(AB+CD)

In the given figure, AB||CD and BC||ED . Find the value of x.