In the circuit shown in figure the maximum output voltage `V_(0)` is

In the circuit shown in the figure, the input voltage V_(i) is 20V, V_(BE)=0 and V_(CE) = 0 . The values of I_(B) , I_(C) and beta are given by

A potential divider circuit is shown in figure.The output voltage V_(0) is:

In the circuit shown in the figure, the input voltage V_(i) is 20V,V_(BE)=0 and V_(CE)=0 . The values of I_(B),I_(C) and beta are given by:

In the circuit shown in the figure, the input voltage V_i is 20 V, V_(BE) = 0 and V_(CE) = 0 . The values of I_B , I_C and beta are given by

In the circuit shown in the figure , the input voltage V_i is 20 V, V_BE =0V and V_CE =0V. What are the value of I_B,I_C,beta ?

For the circuit shown in Fig. find the output voltage,

In the circuit shown in the figure, the input voltage V_i = +5 V, V_(BE) = + 0.8 V and V_(CE) = +0.12 V . Find the values of I_B I_C and beta .