A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in

A capacitor is charged with a battery and then disconnected. A dielectric slab is then inserted between the plates. How are the Charge.

A parallel plate capacitor is charged by a battery, which is then disconnected. A dielectric slab is now introduced between the two plates to occupy the space completely. State the effect on the following: (i) the capacitance of the capacitor. (ii) potential difference between the plates. (iii) the energy stored in the capacitor.

A capacitor is charged with a battery and then disconnected. A dielectric slab is then inserted between the plates. How are the Capacitance.

A capacitor is charged with a battery and then disconnected. A dielectric slab is then inserted between the plates. How are the The stored energy related to the capacitor affected?

A capacitor is charged with a battery and then disconnected. A dielectric slab is then inserted between the plates. How are the Potential difference.

A parallel plate capacitor is charged by a battery, which is then disconnected. A dielectric slab having dielectric constant (relative permittivity) K, is now introduced between its two plates in order to occupy the space completely. State, in terms of K, its effect on the following: The capacitance of the capacitor

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,