`veca` and `vecb` are inclined at an angle `theta=30^@` If `|veca|=1, |vecb|=2` then `|(veca+3vecb)xx(3veca-vecb)|^2=`

Vectors veca and vecb are inclined at an angle theta = 120^(@) . If |veca|=1,|vecb|=2, "then" [(veca+3vecb)xx(3veca-vecb)]^(2) is equal to

Vectors veca and vec b are inclined at an angle theta = 120^@ . If |veca| = |vecb| = 2 , then [(veca + 3vecb) xx (3veca + vecb)]^2 is equal to

vectors veca and vecb are inclined at an angle theta = 60^(@). " If " |veca|=1, |vecb| =2 , " then " [ (veca + 3vecb) xx ( 3 veca -vecb)] ^(2) is equal to

vectors veca and vecb are inclined at an angle theta = 60^(@). " If " |veca|=1, |vecb| =2 , " then " [ (veca + 3vecb) xx ( 3 veca -vecb)] ^(2) is equal to

Let veca and vecb are two vectors inclined at an angle of 60^(@) , If |veca|=|vecb|=2 ,the the angle between veca and veca + vecb is

Let veca and vecb are two vectors inclined at an angle of 60^(@) , If |veca|=|vecb|=2 ,the the angle between veca and veca + vecb is

If veca and vecb are unit vectors inclined at an angle theta , then the value of |veca-vecb| is

If veca and vecb are unit vectors inclined at an angle theta , then the value of |veca-vecb| is