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The equation of the hyperbola whose cent...

The equation of the hyperbola whose centre is `(6,2)` one focus is `(4,2)` and of eccentricity 2 is (A) `3(x-6)^2-(y-2)^2=3` (B) `(x-6)^2-3(y-2)^2=1` (C) `(x-6)^2-2(y-2)^2=1` (D) `2(x-6)^2-(y-2)^2=1`

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