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The equation 3sin^2x+10cosx-6=0 is sat...

The equation `3sin^2x+10cosx-6=0` is satisfied , if

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General solution of 3sin^(2)x+10cosx-6=0 is

alpha is a root of the equation (2sinx-cosx)(1+cosx)=sin^2x beta is a root of the equation 3cos^2x-10cosx+3=0 and gamma is a root of the equation 1-sin2x=cosx-sinx where 0 le alpha, beta, gamma le pi//2 Answer the following question on above passage: sin(alpha-beta)

alpha is a root of the equation (2sinx-cosx)(1+cosx)=sin^2x beta is a root of the equation 3cos^2x-10cosx+3=0 and gamma is a root of the equation 1-sin2x=cosx-sinx where 0 le alpha, beta, gamma le pi//2 Answer the following question on above passage: sinalpha+sinbeta+singamma can be equal

Let alpha be a root of the equation (2sinx-cosx)(1+cosx)=sin^2x beta is a root of the equation 3cos^2x-10cosx+3=0 gamma be a root of the equation 1-sin2x=cosx-sinx 0<=alpha,beta,gamma<=pi/2 sin alpha+sin beta+sin gamma can be equal to (A) (14+3sqrt(2))/6 (B) 43226 (C) (3+4sqrt(2))/6 (D) (1+sqrt(2))/2

Let alpha be a root of the equation (2sinx-cosx)(1+cosx)=sin^2x beta is a root of the equation 3cos^2x-10cosx+3=0 gamma be a root of the equation 1-sin2x=cosx-sinx 0<=alpha,beta,gamma<=pi/2 The value of sin (alpha-beta) is equal to (A) 1 (B) 0 (C) (1-2sqrt(6))/6 (D) (sqrt(3)-2sqrt(2))/6