`int_- 1^2(|x+1|+|x|+|x-1|)dx`

int_(-1)^(2)(|x+1|+|x|+|x-1||dx

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

int_(1)^(3)(|x-1|)/(|x-2|+|x-3|)dx=

int _(1)^(2)e^(x) (1/x - 1/(x^(2)))dx is qual to

int_(-1)^1 max (2-x,2,1+x)dx is

If I_(1)=int_(1-x)^(x) x sin{x(1-x)}dx and I_(2)=int_(1-x)^(x) sin{x(1-x)}dx , then

int_(1)^(3)(x-1)(x-2)(x-3)dx=

int_(1)^(3)(x-1)(x-2)(x-3)dx=

The value of int_(1)^(2)e^(x) [(1)/(x)-(1)/(x^(2))] dx is equal to