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( tan3A + tanA)/(tan3A -tan A)=.....

`( tan3A + tanA)/(tan3A -tan A)=..`

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If : (tan 3 A+tan A)/(tan 3A - tanA)=(sin(mA)/(sin(nA))) then (m,n)= (a) (2,3) (b)(3,4) (c)(4,2) (d) (1,2)

tan3A-tan2A-tanA=?

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Prove that : tan 3A - tan 2A - tan A = tan 3A tan 2A tan A .