Light of wavelength `589.3nm` is incident normally on the slit of width `0.1mm`. What will be the angular width of the central diffraction maximum at a distance of `1m` from the slit?

Light of wavelength 600 nm is incident normally on a slit of width 0.2 mm. The angular width of central maxima in the diffraction pattern is

Light of wavelength 600 nm is incident normally on a slit of width 0.2 mm. The angular width of central maxima in the diffraction pattern is

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m?

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m?

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :

Light of wavelength 6000 Å is incident normally on a single slit of width 0.03 mm. Find the width of the central maxima on the screen which is at a distance 1.5 m away from the slit. What will be the width if the apparatus is immersed in water of refractive index 1.33?

Plane wave of lamda=600 nm incident normally on a slit of width 0.18 mm. Calculate the total angular wideth of the central maximum.

The light of wavelength 600 nm is incident normally on a slit of width 3mm. Calcualte the linear width of central maximum on a screen 3m away from the slit.