If `A_n` is the area bounded by `y= (1-x^2)^n` and coordinate axes, `n in N`, then

If A_n is the area bounded by y=x and y=x^n ,n in \mathbb{N} ,then A_2 A_3 ... A_n= (a) 1/(n(n+1)) (b) 1/(2^n n(n+1)) (c) 1/(2^(n-1)n(n+1)) (d) 1/(2^(n-2)n(n+1))

If A_n is the area bounded by y=x and y=x^n ,n in \mathbb{N} ,then A_2 A_3 ... A_n= (a) 1/(n(n+1)) (b) 1/(2^n n(n+1)) (c) 1/(2^(n-1)n(n+1)) (d) 1/(2^(n-2)n(n+1))

If A_(n) is the area bounded by y=x and y=x^(n), n in N, then A_(2).A_(3)…A_(n)=

If A_(n) is the area bounded by y=x and y=x^(n), n in N, then A_(2).A_(3)…A_(n)=

If A_(n) is the area bounded by y=x and y=x^(n), n in N, then A_(2).A_(3)…A_(n)=

If A_(n) is the area bounded by y=x and y=x^(n),n in N, then A_(2)*A_(3)...A_(n)=(1)/(n(n+1)) (b) (1)/(2^(n)n(n+1))(1)/(2^(n-1)n(n+1)) (d) (1)/(2^(n-2)n(n+1))

If A_n be the area bounded by the curve y=(tanx)^n and the lines x=0,\ y=0,\ x=pi//4 , then for n > 2.

If A_n be the area bounded by the curve y=(tanx)^n and the lines x=0,\ y=0,\ x=pi//4 , then for n > 2.

Let A_n be the area bounded by the curve y = x^n(n>=1) and the line x=0, y = 0 and x =1/2 .If sum_(n=1)^n (2^n A_n)/n=1/3 then find the value of n.

Let A_n be the area bounded by the curve y=(tanx)^n and the lines x=0,y=0, and x=pi/4dot Prove that for n >2,A_n+A_(n-2)=1/(n-1) and deduce 1/(2n+2)