If `(xy)/(x+y) = a, (xz)/(x+z) = b and (yz)/(y+z) = c`, where a,b,c are other than zero, find the value of x

Explanation

Here, `(xy)/(x+y) = a`

`=>1/(x/(xy)+y/(xy)) = a`

`=>1/(1/x+1/y) = a`

`=>1/x+1/y = 1/a->(1)`

Similarly, `1/x+1/z = 1/b->(2)`

and `1/y+1/z = 1/c->(3)`

Subtracting (3) from (1),

`1/x-1/z = 1/a-1/c->(4)`

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