If `sin theta+sqrt(3)costheta=6y-y^2-11 ,theta in [0, 4pi], y in R` holds for

sintheta+sqrt(3)costheta=6x-x^2-11 ,0lt=thetalt=4pi,x in R , (a) hold for no values of x and theta (b) one value of x and two values of theta (c) two values of x and two values of theta (d) two point of values of (x ,theta)

sintheta+sqrt(3)costheta=6x-x^2-11 ,0lt=thetalt=4pi,x in R , (a) hold for no values of x and theta (b) one value of x and two values of theta (c) two values of x and two values of theta (d) two point of values of (x ,theta)

sin theta+sqrt(3)cos theta=6x-x^(2)-11,0<=4 theta pi,x in R hold for no values of x and theta one value of x and two values of theta two values of x and two values of theta two point of values of (x,theta)

sin theta + sqrt(3)cos theta = 6x - x^(2) - 11 , 0lt=thetalt=4pi x""in R holds for :

If x=2sin theta-sin2 theta and y=2cos theta-cos2 theta , theta in[0,2 pi], then (d^(2)y)/(dx^(2)) at theta=pi is

If : sin theta= sqrt3*costheta, "then" : 2(sin theta+costheta)-1=

If r sin theta=sqrt(3),r+4sin theta=2(sqrt(3)+1), and 0<=theta<=2 pi, then theta=

If r sin theta = sqrt(3), r + 4 sin theta = 2(sqrt(3)+1), 0 le theta le 2pi , then theta =

If x sin^(3) theta + y cos^(3) theta = sin theta cos theta ne 0 and x sin theta - y cos theta = 0 , then value of (x^(2) + y^(2)) is :

If sin theta-sqrt(6)costheta=sqrt(7)costheta. Prove that cos theta-sqrt6 sin theta-sqrt7 sin theta=0.