`(m+2)sintheta+(2m-1)costheta=2m+1` then `tan theta` is

If (m+2) sin theta+(2m-1) cos theta=(2m+1) , then show that tan theta= =(4)/(3)or (2m)/(m^(2)-1) .

If cottheta+tantheta=m and sectheta-costheta=n then (i) sintheta costheta=-m (ii) sintheta tantheta=-n (iii) (m^2n)^(2/3)-(mn^2)^(2/3)=1 (iv) (m^2n)^(1/3)+(xy^2)^(1/3)=1

2-cos^(2)theta =3 sintheta costheta , sintheta ne cos theta , then the value of tan theta is

If sintheta+costheta=1 , then the value of sin2theta is

If sintheta+costheta=1 , then the value of sin2theta is

If sintheta+costheta=1 , then the value of sin(2theta) is

If sintheta+costheta=m , then prove that sin^6theta+cos^6theta=(4-3(m^2-1)^2)/4,\ w h e r e\ m^2lt=2.

Prove that (sintheta-costheta+1)/(sintheta+costheta-1)=(1)/(sec theta-tan theta). using the identity sec^(2)theta=1+tan^(2)theta .

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals................ A) m B) n C) 2m D) 2n

if theta_1, theta_2, theta_3, ........, theta_n are in AP then (sintheta_1 + sintheta_2 + ....... + sintheta_n) / (costheta_1 + costheta_2 + costheta_3 + ...... + costheta_n ) =?