if `tantheta+cottheta=2` then `tan^2theta-cot^2theta=`

If tantheta+cottheta=5 , then tan^(2)theta+cot^(2)theta is

tantheta + cot 2theta=2

Solve the following trigonometric equations, (i) cosec^(2)theta=2cottheta (ii) "tan"theta+cottheta=2 (iii) "tan"^(2)theta+cot^(2)theta=2

tantheta-cottheta+2tan2thet+4tan4theta+8cot8theta=0

Eliminate theta "from the equation" m= tantheta +cottheta and n= tan theta - cot theta .

Show that, ((1-tantheta)/(1-cottheta))^2=(1+tan^2theta)/(1+cot^2theta).

If tantheta+cottheta=2 , then the value of tan^(n)theta+cot^(n)theta ( 0^(@)lt theta lt90^(@),n is an integer) is

Statement (A) : If tantheta+cottheta=2 , then for all n epsilon N, tan^(n)theta+cot^(n)theta=2 Reason (R ) : For all n epsilon N, tan theta+cot theta=tan^(n)theta+cot^(n)theta

If tantheta+ cot theta = 2 , then prove that tan^10theta + cot^10 theta =2

prove that tantheta+cottheta = sqrt(sec^(2)theta+cosec^(2)theta)