If `(4+2i)(1+2i)=A+i B,` then

If (4+2i)(1+2i)=A+iB, then

If (1+i)(1+2i)(1+3i)...(1+n i)=a+i b , then the value of; 2. 5. 10. 17... (1+n^2\ ) will be (a) . a-i b (b) . a^2-b^2 (c) . a^2+b^2 (d) . none of these

If one root of x^(2)-(3+2i)x+(1+3i)=0 is 1+i then the other root is A) 1-i B) 2+i C) 3+i D) 1+3i

"If A" = [{:(1, 2), (1, 3):}] , then find A^(-1) + A . (a) I (b) 2I (c) 3I (d) 4I

Express (1 /(2 -2i)+3/(1+i)) ((3+ 4i)/(2-4i)) in the form of a +ib

Express (1 /(2 -2i)+3/(1+i)) ((3+ 4i)/(2-4i)) in the form of a +ib

If ((1+i)(2+3i)(3-4i))/((2-3i)(1-i)(3+4i)) = a + ib , then a^(2) + b^(2) is equal to

If a+(b+2a)i=1-4i, then find a and b.

If (i^(4)+i^(9)+i^(26))/(2-i^(8)+i^(10)-i^(15))=A+i B then (A, B)=

Express (4+2i)/(1-2i) +(3+4i)/(2+3i) in the form a+ib, a in R b in R