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Find a point on the x–axis, which is eq...

Find a point on the x–axis, which is equidistant from the points (7, 6) and (3, 4).

A

`(15/2, 0)`

B

`(17/2, 0)`

C

`(-17/2, 0)`

D

`(-15/2, 0)`

Text Solution

Verified by Experts

The correct Answer is:
A `(15/2, 0)`
Let the point on x-axis be `P(x, 0)`
Let `A` be `(7, 6)` and B be `(3, 4)`
Now `PA = sqrt((x-7)^2 + (0-6)^2)`
`PA^2 = (x – 7)^2 + 36`
...
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