A parallel plate capacitor of capacitance C is charged to a potential V and then disconnected with the battery. If separation between the plates is decreased by `50%` and the space between the plates is filled with a dielectric slab of dielectric constant `K=10`. then

A parallel plate capacitor is charged completely and then disconnected from the battery. IF the separation between the plates is reduced by 50% and the space between the plates if filled with a dielectric slab of dielectric constant 10, then the potential difference between the plates

The parallel plate capacitors of capacitances C and 2C are connected in parallel and charged to a potential difference V by a battery. The battery is the disconnected and the space between the plates of capacitance C is filled with a dielectric of dielectric constant K. Find the potential difference across the combination now.

A parallel plate capacitor of capacitance C is charged to a potential V by a battery. Without disconnecting the battery, distance between the plates of capacitor is tripled and a dielectric medium of K = 10 is introduced between the plates of capacitor. Explain giving reasons how will the following be affected ? (a) Capacitance of capacitor (b) Charge on capacitor (c ) Energy density of capacitor.

A parallel plate condenser is charged by connected it to a battery. Without disconnected the battery, the space between the plates is completely filled with a medium of dielectric constant k . Then

A capacitor of plate area A and separation between plates d is half filled with dielectric of dielectric constant K. What is equivalent capacitance?