The vertex `C` of a triangle `ABC` is `(4,-1).` The equation of altitude `AD` and Median `AE` are `2x-3y+12=0 and 2x+3y=0` respectively then slope of side `AB` is :-

in a triangle ABC, if A is (1,2) and the equations of the medians through B and c are x+y=5 and x=4 respectively then B must be:

The vertex A of a triangle ABC is the point (-2,3) . Whereas the line perpendicular to the sides AB and AC are x - y - 4 = 0 and 2x - y - 5 = 0 respectively. The right bisectors of sides meet at P (3/2,5/2) . Then the equation of the median of side BC is

In a triangle ABC , if the equation of sides Ab,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The image of point b w.r.t the side cA is

In Delta ABC equation of the right bisectors of the sides Ab and AC are x+y = 0 and x - y = 0 respectively .If A = (5,7) then equation of side BC is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively ,Tangent of internal angle A is equal to

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively ,Tangent of internal angle A is equal to

In a triangle AbC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , Tangent of internal angle A is equal to