Home
Class 12
MATHS
The area under the curve y=|cosx-sinx|, ...

The area under the curve `y=|cosx-sinx|, 0 le x le pi/2`, and above x-axis is: (A) `2sqrt(2)+2` (B) `0` (C) `2sqrt(2)-2` (D) `2sqrt(2)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The area bounded by the curve y = sin^(2) x, 0 le x le pi/2 , X axis and the line x = pi/2 is

Area under the curve when 2x^2le y le4-2x

The area formed by triangular shaped region bounded by the curves y=sinx, y=cosx and x=0 is (A) sqrt(2)-1 (B) 1 (C) sqrt(2) (D) 1+sqrt(2)

The area between the curves y=tanx,y=cotx and X-axis in 0le x le (pi)/(2) is

The area enclosed by the curve y=sinx+cosxa n dy=|cosx-sinx| over the interval [0,pi/2] is (a)4(sqrt(2)-2) (b) 2sqrt(2) ( sqrt(2) -1) (c)2(sqrt(2) +1) (d) 2sqrt(2)(sqrt(2)+1)

The area enclosed by the curve y=sinx+cosxa n dy=|cosx-sinx| over the interval [0,pi/2] is (a)4(sqrt(2)-2) (b) 2sqrt(2) ( sqrt(2) -1) (c)2(sqrt(2) +1) (d) 2sqrt(2)(sqrt(2)+1)

The area enclosed by the curve y=sinx+cosxa n dy=|cosx-sinx| over the interval [0,pi/2] is (a)4(sqrt(2)-2) (b) 2sqrt(2) ( sqrt(2) -1) (c)2(sqrt(2) +1) (d) 2sqrt(2)(sqrt(2)+1)