ABCD is a parallelogram and O is the point of intersection of its diagonals. If `ar(triangle AOD)= 4cm^2` find `ar(triangle AOB)`

ABCD is a parallelogram and O is the point of intersection of its diagonals.If ar(/_AOD)=4cm^(2) find ar(/_AOB)

In the figure. ABCD is a parallelogram and O is any point on BC . Prove that ar (triangleABO) + ar (triangleDOC) = ar(triangleODA)

ABCD is a parallelogram and O is a point in its interior. Prove that (i) ar(triangleAOB)+ar(triangleCOD) =(1)/(2)ar("||gm ABCD"). (ii) ar(triangleAOB)+ar(triangleCOD)=ar(triangleAOD)+ar(triangleBOC) .

ABCD is a parallelogram. P is any point on CD. If ar(triangleDPA) = 15 cm^2 and ar(triangleAPC) = 20 cm^2 , the ar (triangleAPB) =

ABCD is a parallelogram and X is the mid-point of AB. If ar (AXCD) = 24 cm^2 , then ar (ABC) = 24 cm^2 .

ABCD is a parallelogram,P is the mid point of AB.BD and CP intersects at Q such that CQ:QP=3:1. If ar(Delta PBQ)=10cm^(2), find the area of parallelogram ABCD.

The sides AD, BC of a trapezium. ABCD are parallel and the diagonals AC and BD meet at O. If the area of triangle AOB is 3 cm and the area of triangle BDC is 8 cm2, then what is the area of triangle AOD?

In the figure ABCD is a trapezium. Diagonal AC and BD intersect at O. Area of triangle A B C is 24 cm^2 and area of triangle AOB is 10 sq.cm. a) Find the area of triangle BOC. b) How much is the area of triangle AOD? Write reason.

In the given figure, ABCD is a ||gm in which diagonals AC and BD intersect at O. If ar(||gm ABCD) is 52 cm^(2) then the ar(triangleAOB) =?

In the given fig. ABCD is a parallelogram and ABE is a triangle. Also AB||CE . If ar (ABCD) = 60 cm^2 then ar (DeltaABE) is :