The curves `ax^(2)+by^(2)=1 and Ax^(2)+B y^(2) =1` intersect orthogonally, then

If the curve ax^(2)+by^(2)=1 and a'x^(2)+b'y^(2)=1 intersect orthogonally, then

If two curves ax^(2)+by^(2)=1 and a'x^(2)+b'y^(2)=1 intersect orthogonally,then show that (1)/(a)-(1)/(b)=(1)/(a')-(1)/(b')

If the curves 2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4 intersect orthogonally, then a =

If the curves 2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4 intersect orthogonally, then a =

Show the condition that the curves ax^(2)+by^(2)=1 and a'x^(2)+b'y^(2)=1 should intersect orthogonally is (1)/(a)-(1)/(b)=(1)/(a')-(a)/(b)

Show that it the curves ax^(2) +by^(2)=1 " and " Ax^(2) +By^(2) =1 are orthogonal then ab(A-B)=AB(a-b).

If the curvs a x^2 + b y^2 = 1 and a' x^2 + b' y^2 =1 intersect orthogonally, then prove that frac{1}{a} - frac{1}{b} = frac{1}{a'} - frac{1}{b'}

If the curves ax^2 + by^2 =1 and a'x^2 +b'y^2 =1 intersect orthogonally, prove that: 1/a-1/a'=1/b-1/b'

The curves ax^2+by^2=1 and Ax^2+By^2=1 intersect orthogonally, then