The curve orthogonal to `y^3 = x^2` at `(1, 1)` is

The locus of the center of a circle which cuts orthogonally the parabola y^2=4x at (1,2) is a curve

The locus of the center of a circle which cuts orthogonally the parabola y^2=4x at (1,2) is a curve

The locus of the center of a circle which cuts orthogonally the parabola y^(2)=4x at (1,2) is a curve

A : The curve y=x^2,6y=7-x^3 cut orthogonally at (1,1) . R : Two curve cut each other orthogonally at their point of intersection P iff m_1m_2=-1 where m_1,m_2 are the gradiants of the two curves at P .

If the curve a y+x^2=7 and x^3=y cut orthogonally at (1,\ 1) , then a is equal to (a) 1 (b) -6 (c) 6 (d) 0

If the curve a y+x^2=7 and x^3=y cut orthogonally at (1,\ 1) , then a is equal to (a) 1 (b) -6 (c) 6 (d) 0

If the curves ay + x^(2) = 7 and x^(3) = y cut orthogonally at (1, 1), then find the value a.

If the curves ay + x^(2) =7 and x^(3) =y cut orthogonally at (1,1) then the value of a is

If the curves ay+x^2=7 and x^3=y cut orthogonally at (1, 1) then a= (A) 1 (B) -6 (C) 6 (D) 1/6