For the reaction
Calculate `K_(P)`at900K where the equilibrium straem -hydrogen mixture was 45% `H_(2)` by volume :

For the reaction SnO_(2(s)) + 2H_(2(g)) hArr 2H_(2) O_((g)) + Sn_((d)) . Calculate K_(p) at 900K, where the equilibrium steam hydrogen mixture was 45% H_(2) by volume.

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) The equilibrium constant K_(p) changes with

Pure PCl_(5) is introduced into an evacuated chamber and to equilibrium at 247^(@)C and 2.0 atm .The equilibrium gases mixture contains 40% chlorine by volume . Calculate K_(p) at 247^(@)C for the reaction PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)

At 87^(@)C , the following equilibrium is established H_(2) (g)+S(s)hArrH_(2)S(s)(g), K_(p)=7xx10^(-2) If 0.50 mole of hydrogen and 1.0 mole of sulphuur are heated to 87^(@)C and 2.0 atm .the equilibrium gases mixture contains 40% chlorine by volume. Calculate K_(p) at 247^(@)C for the reaction PCl_(5)(g)hArrPCl_(3)(G)+Cl_(2)(g)