The first three terms in the expansion of `(1+a x)^n(n!=0)` are `1,6xa n d16 x^2dot` Then find the value of `aa n dndot`

The first three terms in the expansion of (1+a x)^n(n!=0) are 1,6x and 16 x^2dot Then find the value of a and ndot

The first three terms in the expansion of (1+ax)^(n)(n!=0) are 1,6x and 16x^(2). Then find the value of a and n.

The first three terms in the expansion of (1+ax)^(n)(n ne 0) are 1,6x, and 16x^(2) . Then find the value of a and n.

The first three terms in the expansion of (1+ ax) ^(n) are 1, 6x and 16x^(2), then the values of a and n are -

n th term in the expansion of (x+(1)/(x))^(2n)

The first three terms in the expansion of (1+a x)^(n ne 0) are 1,6 x, 16 x^(2) . Then the values of a and n are respectively.

If the first three terms in the expansion of (1+ax)^n are 1,6x and 16x^2 , find a and n

The first three terms in the expansion of (1+a x)^n are 1,12 x,64 x^2 . Find n and a.

If the first three terms in the expansion of (1+ax)^n are 1,12 x , 64x^2 , find 'n' and 'a'