The position of a particle at time moving in `x-y` plane is given by `vec(r) = hat(i) + 2 hat(j) cos omegat`. Then, the motikon of the paricle is :

The position vector of a particle moving in x-y plane is given by vec(r) = (A sinomegat)hat(i) + (A cosomegat)hat(j) then motion of the particle is :

The position vector of a particle moving in x-y plane is given by vec(r) = (A sinomegat)hat(i) + (A cosomegat)hat(j) then motion of the particle is :

A particle moves in x-y plane according to the equation bar(r ) = (hat(i) + 2 hat(j)) A cos omega t the motion of the particle is

The position vector of a particle moving in x-y plane is given by vec(r)=(t^(2)-4)hat(i)+(t-4)hat(j) . Find (a) Equation of trajectory of the particle (b)Time when it crosses x-axis and y-axis

Position vector of a particle moving in x-y plane at time t is r=a(1- cos omega t)hat(i)+a sin omega t hat(j) . The path of the particle is

Position vector of a particle moving in x-y plane at time t is r=a(1- cos omega t)hat(i)+a sin omega t hat(j) . The path of the particle is

The time dependence of the position of a particle of mass m = 2 is given by vec(r) (t) = 2t hat(i) - 3 t^(2) hat(j) Its angular momentum, with respect to the origin, at time t = 2 is :