When a jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum.

`F=(rhoAV_(0))V_(0)-(rhoAV_(0))V_(0)costheta=rhoAV_(0)^(2)[1-costheta]` If surface is free and starts moving due to thrust of the liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let, at any instant, the velocity of surface be `u`. Then the above equation becomes `
F=rhoA(V_(0)-u)^(2)[1-costheta]` Based on the above concept, as shown in the following figure, if the cart is frictionless and free to move in the horizontal direction, then answer the following.

Given that cross sectional area of jet `=2xx10^(-4)m^(2)` velocity of jet `V_(0)=10m//s` density of liquid `=1000kg//m^(3)` ,mass of cart `M=10 kg`.
Initially (`l=0`) the force on the cart is equal to

When a jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F=(rhoAV_(0))V_(0)-(rhoAV_(0))V_(0)costheta=rhoAV_(0)^(2)[1-costheta] If surface is free and starts moving due to thrust of the liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let, at any instant, the velocity of surface be u . Then the above equation becomes F=rhoA(V_(0)-u)^(2)[1-costheta] Based on the above concept, as shown in the following figure, if the cart is frictionless and free to move in the horizontal direction, then answer the following. Given that cross sectional area of jet =2xx10^(-4)m^(2) velocity of jet V_(0)=10m//s density of liquid =1000kg//m^(3) ,mass of cart M=10 kg . Velocity of cart at t = 10 s is equal to

When a jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F=(rhoAV_(0))V_(0)-(rhoAV_(0))V_(0)costheta=rhoAV_(0)^(2)[1-costheta] If surface is free and starts moving due to thrust of the liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let, at any instant, the velocity of surface be u . Then the above equation becomes F=rhoA(V_(0)-u)^(2)[1-costheta] Based on the above concept, as shown in the following figure, if the cart is frictionless and free to move in the horizontal direction, then answer the following. Given that cross sectional area of jet =2xx10^(-4)m^(2) velocity of jet V_(0)=10m//s density of liquid =1000kg//m^(3) ,mass of cart M=10 kg . The time at which velocity of cart becomes 2 m/s is equal to

When a jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F=(rhoAV_(0))V_(0)-(rhoAV_(0))V_(0)costheta=rhoAV_(0)^(2)[1-costheta] If surface is free and starts moving due to thrust of the liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let, at any instant, the velocity of surface be u . Then the above equation becomes F=rhoA(V_(0)-u)^(2)[1-costheta] Based on the above concept, as shown in the following figure, if the cart is frictionless and free to move in the horizontal direction, then answer the following. Given that cross sectional area of jet =2xx10^(-4)m^(2) velocity of jet V_(0)=10m//s density of liquid =1000kg//m^(3) ,mass of cart M=10 kg . The time at which velocity of cart becomes 2 m/s is equal to

When a jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F=(rhoAV_(0))V_(0)-(rhoAV_(0))V_(0)costheta=rhoAV_(0)^(2)[1-costheta] If surface is free and starts moving due to thrust of the liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let, at any instant, the velocity of surface be u . Then the above equation becomes F=rhoA(V_(0)-u)^(2)[1-costheta] Based on the above concept, as shown in the following figure, if the cart is frictionless and free to move in the horizontal direction, then answer the following. Given that cross sectional area of jet =2xx10^(-4)m^(2) velocity of jet V_(0)=10m//s density of liquid =1000kg//m^(3) ,mass of cart M=10 kg . The power supplied to the cart when its velocity becomes 5 m//s is equal to

When a jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F=(rhoAV_(0))V_(0)-(rhoAV_(0))V_(0)costheta=rhoAV_(0)^(2)[1-costheta] If surface is free and starts moving due to thrust of the liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let, at any instant, the velocity of surface be u . Then the above equation becomes F=rhoA(V_(0)-u)^(2)[1-costheta] Based on the above concept, as shown in the following figure, if the cart is frictionless and free to move in the horizontal direction, then answer the following. Given that cross sectional area of jet =2xx10^(-4)m^(2) velocity of jet V_(0)=10m//s density of liquid =1000kg//m^(3) ,mass of cart M=10 kg . The power supplied to the cart when its velocity becomes 5 m//s is equal to

Surface tension in a liquid is due to :

Origin of surface tension of a liquid is due to

Thrust force on curved surface

Thrust of a liquid always acts ____ to the surface of contact.