Home
Class 11
PHYSICS
A steel wire of length 1 m and mass 0.1 ...

A steel wire of length `1 m` and mass `0.1 kg` and having a uniform cross-sectional area of `10^(-6) m^(2)` is rigidly fixed at both ends. The temperature of the wire is lowered by `20^(@)C`. If the wire is vibrating in fundamental mode, find the frequency (in Hz). `(Y_(steel)=2xx 10^(11) N//m^(2),alpha_(steel)=1.21 xx 10^(-5)//.^(@)C)`.

Promotional Banner

Similar Questions

Explore conceptually related problems

A steel wire of length 1m , mass 0.1kg and uniform cross-sectional area 10^(-6)m^(2) is rigidly fixed at both ends. The temperature of the wire is lowered by 20^(@)C . If transverse calculate the frequency of the fundamental mode of vibration. Given for steel Y = 2 xx 10^(11)N//m^(2) alpha = 1.21 xx 10^(-5) per ^(@)C

A steel wire of length im, mass 0.1kg and uniform cross sectional area 10^(-6) m^(2) is rigidly fixed at both ends. The temperature of the wire is lowered by 20^(@)C . If the transverse waves are set up plucking the string in the middle, calculate the frequency of the fundamental mode of vibration. (Y=2xx10^(11)N//m^(2), a=1.21xx10^(-5)//^(@)C)

A steel wire of length lm, mass 0.1 kg and uniform cross-sectional area 10^(-6)m^(2) is rigidly fixed at both ends. The temperature of the wire is lowered by 20^(0)C . If the transverse waves are set up by plucking the string in the middle, calculate the frequency of the fundamental mode of vibration [Y=2xx10^(11)N//m^(2) and alpha=1.21xx10^(-5)l^(0)C]

A steel wire of length 1m , mass 0.1kg and uniform cross-sectional area 10^(-6)m^(2) is rigidly fixed at both ends. The temperature of the wire is lowered by 20^(@)C . If transverse waves are set up by plucking the string in the middle.Calculate the frequency of the fundamental mode of vibration. Given for steel Y = 2 xx 10^(11)N//m^(2) alpha = 1.21 xx 10^(-5) per ^(@)C

A steel wire of length 20 cm and uniform cross-sectional area of 1 mm^(2) is tied rigidly at both the ends at 45^(@)C . If the temperature of the wire is decreased to 20^(@)C , then the change in the tension of the wire will be [Y for steel = 2 xx 10^(11 Nm^(-2) , the coefficient of linear expansion for steel = 1.1 xx 10^(-5)//.^(@)CC^(-1) ]

A steel wire of length 0.20m and uniform cross section 10^(-6)m^(2) is tied rigidly at both ends. The temperature of the wire is changed from 40^(@) C to 20^(@)C . Calculate the thermal tension in the wire given alpha =1.1. xx 10^(-5)//.^(@)C and Y=2xx10^(11)Nm^(-2)

A steel wire of length 20 cm and uniform cross-sectional 1 mm^(2) is tied rigidly at both the ends. The temperature of the wire is altered from 40^(@)C to 20^(@)C . Coefficient of linear expansion of steel is alpha = 1.1 xx 10^(-5) .^(@)C^(-1) and Y for steel is 2.0 xx 10^(11) Nm^(2) , the tension in the wire is