The height of a waterfall is 84 metre . Assuming that the entire kinetic energy of falling water is converted into heat, the rise in temperature of the water will be (`g=9.8 m//s^(2),J=4.2` joule / cal)

A water fall is 84 m high. Assuming that half the kinetic energy of falling water get converted to heat, the rise in temperature of water is

In a water-fall the water falls from a height of 100 m . If the entire K.E. of water is converted into heat, the rise in temperature of water will be

10 g of water is supplied with 420 J of energy. The rise in temperature of water is

Water drops from a height of 40 m in a waterfall. if 75% of its energy is converted into heat and absorbed by the water, the rise in temperature of the water will be

Water at Bhakra dam falls through a height of 210 m. Assuming that the whole of the energy due to fall is converted into heat, calculate the rise in temperature of water. Take J = 4.2 J cal^(-1) and g = 9.8 ms^(-2) .

Water falls on the ground from 42 m height. It half of loss is potential energy converts into heat, then increase in temperature of water is

Water fall from a height 50m, If one third of its mechanical energy converted into heat what will be the rise in temperature of water