`50 mL` of `1 M HCl, 100 mL` of `0.5 M HNO_(3)`, and `x mL` of `5 M H_(2)SO_(4)` are mixed together and the total volume is made upto `1.0 L` with water. `100 mL` of this solution exactly neutralises `10 mL` of `M//3 Al_(2) (CO_(3))_(3)`. Calculate the value of `x`.

25mL of 2N HCl, 50 mL "of" 4N HNO_(3) and x mL 2 M H_(2)SO_(4) are mixed together and the total volume is made up to 1L after dilution. 50mL if this acid ixture completely reacteed with 25mL of a 1 N Na_(2)CO_(3) solution. The value of x is:

5 mL of N-HCl , 20 mL of N//2 H_(2)SO_(4) and 30 mL of N//3 HNO_(3) are mixed together and the volume is made to 1 L . The normality of the resulting solution is

5 mL of N-HCl , 20 mL of N//2 H_(2)SO_(4) and 30 mL of N//3 HNO_(3) are mixed together and the volume is made to 1 L . The normality of the resulting solution is

10mL of 0.5NHCl, 30mL of 0.1NHNO_(3) and 75mL of 0.1M H_(2)SO_(4) are mixed together. The normality of the resulting solution will be :

10 " mL of " 2 M HCl and 20 " mL of " 1 M HNO_3 and V volume of 5M H_2SO_4 are mixed together and the solution was made upto 5 L. 10 " mL of " this acid solution exactly neutralises 28.6 " mL of " Na_2CO_3 solution containing 1 g of Na_2CO_4.10H_2O in 100 " mL of " water. Calculate the amount of SO_4^(2-) ions in grams present in solution.

10 " mL of " 2 M HCl and 20 " mL of " 1 M HNO_3 and V volume of 5M H_2SO_4 are mixed together and the solution was made upto 5 L. 10 " mL of " this acid solution exactly neutralises 28.6 " mL of " Na_2CO_3 solution containing 1 g of Na_2CO_4.10H_2O in 100 " mL of " water. Calculate the amount of SO_4^(2-) ions in grams present in solution.

When 100 mL of 0.1 M KNO_(3) and 400 mL of 0.2 MHCl and 500 mL of 0.3 M H_(2) SO_(4) are mixed, then in the resulting solution

When 100 mL of 0.1 M KNO_(3) and 400 mL of 0.2 MHCl and 500 mL of 0.3 M H_(2) SO_(4) are mixed, then in the resulting solution