If the linear density (mass per unit len...

If the linear density (mass per unit length) of a rod of length `3 m` is proportional to `x`, where `x`, where `x` is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is.

Similar Questions

Explore conceptually related problems

The mass per unit length of a non-uniform rod of length L is given by mu = lambdax^2 , where lambda is constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is

The mass per unit length of a non - uniform rod of length L is given mu = lambda x^(2) , where lambda is a constant and x is distance from one end of the rod. The distance of the center of mas of rod from this end is

The mass per unit length of a non-uniform rod of length L is given by mu= lamdaxx2 , where lamda is a constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is :-

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.

The mass per unit length of a non- uniform rod OP of length L varies as m=k(x)/(L) where k is a constant and x is the distance of any point on the rod from end 0 .The distance of the centre of mass of the rod from end 0 is

The centre of mass of a non-uniform rod of length L whose mass per unit length lambda is proportional to x^2 , where x is distance from one end

A rod of length 3m and its mass par unit length is directly proportional to the distance x from its one end . The centre of gravity of the rod from that end will be at :-

If the linear density (mass per unit length) of a rod of length `3 m` is proportional to `x`, where `x`, where `x` is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is.

Similar Questions

Recommended Questions