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From the mixture of 4 moles Ca(3)(PO(4))...

From the mixture of 4 moles `Ca_(3)(PO_(4))_(2)` and 5 moles of `P_(4) O_(10)` and 6 moles of `H_(3)PO_(3)` all the phosphorus atoms are removed then moles of `P_(4)` molecule formed from all these atoms is

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The number of carbon atoms in exactly 12 g C^(12) is called Avogadro's number , N_(A) (6.022 xx 10^(23)) . One mole is the amount of material which contains Avogradro's number of particle. These definitions emphasize that the mole refers to a fixed number of NA^(+) b Avogadro's number of atoms , electrons to refer to a mole of helium , a mole of electrons , or a mole of NA^(+) by Avogadro's number of atoms, electrons or ions respectively. On the other hand, phrases like "one mole of hydrogen" can be ambiguous , and should be restated as "one mole of hydroden atoms" or " one mole fo hydrogen molecules." But it is a matter of common practice among chemists , however , to let the name of the element stand for its mos common form. Thus one mole of O_(2) is frequently referred to as one mole of oxygen , whereas one moles of O is called one mole of oxygen atoms. Suppose if we take one mole molecules fo H_(2)SO_(4) then it contain 2 moles of H atom 1 mole of S atom and 4 moles of O atom. It can also be said that moles of oxygen molecules is (4)/(2) =2 mole. From a mixture of 4 moles Ca_(3)(PO_(4))_(2) , 5 moles of p_(4)O_(10) and 6 moles of H_(3)PO_(3) , all the phosphourus atoms are removed . Then moles of P_(4) molecules formed from all these atoms are:

If, from 10 moles NH_(3) and 5 moles of H_(2)SO_(4), all the H-atoms are removed in order to form H_(2) gas, then find the number moles of H_(2) formed.

How many moles of H_3 PO_4 are obtained on hydrolysis of one mole of P_4 O_8 .

How many moles of H_3 PO_4 are obtained on hydrolysis of one mole of P_4 O_8 .

If 0.5 mole of BaCl_(2) mixed with 0.20 mole of Na_(3) PO_(4) the maximum number of moles of Ba_(3)(PO)_(2) then can be formed is