`1/(6i)+1/(7i)=x/(8i)`

Given that x, y in R . Solve (x)/(1+2i) + (y)/(3+2i)= (5+6i)/(8i-1)

Given that x, y in R . Solve: x/(1+2i)+y/(3+2i)=(5+6i)/(8i-1)

Given that x,y in R. Solve: (x)/(1+2i)+(y)/(3+2i)=(5+6i)/(8i-1)

Given that x, y in R . Solve: x/(1+2i)+y/(3+2i)=(5+6i)/(8i-1)

Given that x, y in R . Solve: x/(1+2i)+y/(3+2i)=(5+6i)/(8i-1)

Perform the indicated operations and write the result in the form x+iy: (i) (-3+2i)+(-6+3i) (ii) ((1)/(2)+(7)/(2)i)-(4+(5)/(2)i) (iii) (1-2i)-i+(4-7i)-2i+(5i+3) .

Express the following in the form of a" "+" "b i : (i) (-5i)(1/8i) (ii) (-i)(2i)(-1/8i)^3

Express the following in the form of a + b i :(i) (-5i)(1/8i) (ii) (-i)(2i)(-1/8i)^3

The value of (i^(5)+i^(6)+i^(7)+i^(8)+i^(9))/(1+i) is (1)/(2)(1+i)(b)(1)/(2)(1-i)(c)1(d)(1)/(2)

Simplify : {:((i),3(6+6i)+i(6+6i),(ii),(1-i)-(-3+6i)),((iii),((1)/(3)-(2)/(3)i)-(4+(3)/(2)i),(iv),{((1)/(5)+(7)/(5)i)-(6+(1)/(5)i)}-((-4)/(5)+i)):}