Two identical point masses, each of mass M are connected to one another by a massless string of length L. A constant force F is applied at the mid-point of the string. If l be the instantaneous distance between the two masses, what will be the acceleration of each mass?

Two particles each of mass m are connected by a light string of length 2L as shown in the figure. A constant force F is applied continuoulsly at the mid - point of the string at right - angle to intial position of the string. Find the acceleration of each particle and the acceleration of approach between the particles when separation between them is 2x

Two particles, each of mass m, are connected by a light string of length 2L as shown in A continuous force F is applied at the mid point of the string (x=0) at right angles to the initial position of the string. Show that acceleration of m in the direction at right angles to F is given by a_(x)=F/(2m)x/sqrt(L^(2)-x^(2)) where x is the perpendicular distance of one of the particles from the line of action of F. Discuss the situation when x=L

Two particles of equal masses m and m are connected by a light string of length 2l. A constant force F is applied continuously at the mid-point of the string, always along the perpendicular bisector of the straight line joining the two particles. Show that when the distance between the two particles is x, the acceleration of the particle is a = F/m = (x)/((1^2 - x^2) ^(1//2)

Two point masses, each of mass 'm' are connected to the end of spring. If force F is applied on one of the mass, then find the acceleration of this mass if the acceleration of other mass is a ?

An object of mass 10kg is connected to the lower end of a massless string of length 4m hanging from the ceiling. If a force F is applied horizontally at the mid-point of the string, the top half of the string makes an angle of 45^(@) with the vertical , then the magnitude of F is

An object of mass 10kg is connected to the lower end of a massless string of length 4m hanging from the ceiling. If a force F is applied horizontally at the mid-point of the string, the top half of the string makes an angle of 45^(@) with the vertical , then the magnitude of F is