A person in an elevator accelerating upwards with an acceleration of ` 2ms^(-2)` , tosses a coin vertically upwards with a speed of `20 ms^(-1)` . After how much time will the coin fall back into his hand ? (g = 10 `ms^(-2)`)

A person in an elevator accelerating upwards with an acceleration of 2 m/s^(2) , tosses a coin vertically upwards with a speed of 20 ms^(-1) . After how much time will the coin fall back into his hand ? (g = 10 ms^(2) )

A person in an elevator accelerating upwards with an acceleration of 2ms^-2 , tosses a coin vertically upwards with a speed of 20 m s^-1 . After how much time will the coin fall back into his hand? (g = 10 ms^-2)

A person in an elevator accelerating upwards with an acceleration of 4 ms^(-2) tosses a coin vertically. Upwards with a speed of 21 ms^(-1) with respect to himself. The time at which coin will back into his hand is (g = 10 ms^(-2))

A man is riding an elevator which is rising up with a uniform acceleration of 2 ms^(-1) He tosses a coin vertically upwards with a speed of 20 ms. What time the coin would take to fall back into his hands? (Take g = 10 ms^(-2))

An elevator is accelerating upwards with a constant acceleration a ms^-2 . If a coin is dropped in it by a passenger, then.

A person of 60 kg enters a lift going up with an acceleration 2 ms^(- 2) The vertical upward force acting on the person will be (g = 10 ms ^(-2))