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Let "Delta"r=|r-1n6(r-1)^2 2n^2 4n-2(r-1...

Let `"Delta"_r=|r-1n6(r-1)^2 2n^2 4n-2(r-1)^2 3n^3 3n^2-3n|dot` Show that `sum_(r=1)^n"Delta"_r` is contant.

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Let Delta_r=|[r-1,n,6],[(r-1)^2,2n^2,4n-2],[(r-1)^3,3n^3,3n^2-3n]| . Show that sum_(r=1)^n Delta_r is contant.

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Let Delta_(a)=|{:((a-1),n,6),((a-1)^(2), 2n^(2),4n-2),((a-1)^(3),3n^(3),3n^(2)-3n):}| the value of sum_(a=1)^(n)Delta_(a) is