A dice is weighted so that the probability of differents faces to turn up is as given Number : `1,2,3,4,5,6` and Probability : `0.2,0.1,0.3,0.1,0.2` If `P(A/B)=p_1 and P(B/C)=p_2 and P(C/A)=p_3` then the value of `p_1,p_2,p_3` respectively are Take the events `A,B and C` as `A={1,2,3},B={2,3,5} and C={2,4,6}` (A) `2/3,1/3,1/4` (B) `1/3,1/3,1/6` (C) `1/4,1/3,1/6` (D) `2/3,1/6,1/4`