If `a+b+c=0`, then, the equation `3ax^(2)+2bx+c=0` has , in the interval (0,1).

If 2a+3b+6c=0 then the equation ax^2+bx+c=0 has in the interval (0,1)

If 2a + 3b + 6c = 0, show that there exists at least one root of the equation ax^(2) + bx + c = 0 in the interval (0,1).

If 2a+3b+6c=0, then prove that at least one root of the equation ax^(2)+bx+c=0 lies in the interval (0,1) .

If a+b+c=0 then roots of the equation 3ax^(2)+4bx+5c=0 are

If 2a+3b+6c =0 then the equation ax ^2 + bx +c=0 has atlest one root in

If 4a+2b+c=0 , then the equation 3ax^(2)+2bx+c=0 has at least one real lying in the interval

If 4a+2b+c=0 , then the equation 3ax^(2)+2bx+c=0 has at least one real lying in the interval

If a + b + c = 0 then the quadratic equation 3ax^(2) + 2bx + c = 0 has