Balance the following redox equaiton by both methods.
`[Cr(OH)_(4)]^(ө)+H_(2)O_(2)rarrCrO_(4)^(2-)+H_(2)O`(basic medium)

Balance the following equations by oxidation number method. MnO_(4)^(-)+H_(2)O_(2)+H^(+)toMn^(2+)+H_(2)O+O_(2)

Balance the following by ion electron method (basic medium): Cr(OH)_(3)+IO_(3)^( ө)rarrI^(ө)+CrO_(4)^(2-)

Balance the following by ion electron method (basic medium): Cr(OH)_(3)+IO_(3)^( ө)rarrI^(ө)+CrO_(4)^(2-)

Balance the following redox reaction by using oxidation number method. MnO_(2)+Br^(-)toMn^(+2)+Br_(2)+H_(2)O (acid medium)

[" 12,Balance the following redox reaction by ion - electron method: "],[Cr_(2)O_(7)d(aq)+SO_(2)(q)rarr Cr^(3+)(aq)+SO_(4)^(2)(aq)" (acidic medium) "]

Balance the redox reaction by half reaction method : Br_(2)+ H_(2)O_(2) to BrO_(3)^(-) + H_(2)O (in acidic medium)

Balance the redox reaction by half reaction method : Br_(2)+ H_(2)O_(2) to BrO_(3)^(-) + H_(2)O (in acidic medium)