Factors of `4x^3-7x^2-34x-8` are

The factor of 4x^(3)-7x^(2)-34x-8 is

Find the value of a such that (x-4) is a factor of 5x^3-7x^2-a x-28

Show that 2x + 7 is a factor of 2x^3 + 7x^2 - 4x - 14 Hence, solve the equation: 2x^3 + 7x^2 - 4x - 14 = 0.

The factors of 2x^2 - 7x + 3 are :

Posible factors of x^(4)+x^(3)-7x^(2)-x+6 are

Factorize: x^6-7x^3-8

If (x-sqrt2) is a factor of x^4-7x^3+10x^2+14x-24 . Find the other factors.

Let (x-1) is a factor of x^(4)-7ax^(2)+3bx+9 and (x-2) is a factor of (x^(3))/(8)+(3bx^(2))/(4)+ax+1 ,then (27)/(2)|a+b| is