Calculate the least amount of work that must be done to freeze one gram of wate at `0^@C` by means of a refrigerator. Temperature of surroundings is `27^@C`. How much heat is passed on the surroundings in this process? Latent heat of fusion `L=80cal//g`.

Calculate the least amount of work that must be done to freeze one gram of water at 0 ^@ C by means of the refrigerator.The temperature of the surrounding is 27 ^@ C .How much heat is passed on the surrounding in this process? Latent heat of fusion L=80 cal/g.

Calculate the heat absorbed if the initial temperature of 50g ice is 0^@C to change into water of the same temperature (Latent heat of fusion of ice is 80 cal//g )

Calculate the amount of heat energy to be supplied to convert 2 kg of ice at 0^@C completely into water at 0^@C if latent heat of fusion for ice is 80 cal/g.

Calculate the amount of heat energy to be supplied to convert 4 kg of ice at 0^@C completely into water at 0^@C if latent heat of fusion for ice is 80 cal/g.

Calculate the amount of heat required to convert 80g of ice at 0^(@)C into water at the same temperature . ( Specific latent heat of fusion of ice = 80 cal //g )

Calculate the amount of heat required to convert 80 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the amount of heat required to convert5g of ice of 0^(@)C into water at 0^(@)C . ( Specific latent heat of fusion of ice 80 cal //g )

Consider the following arrangement of resistors . This arrangement is immersed in a box containting ice at 0^@)C . How much ice must be put in the box constant? (Latent heat of ice L = 80 cal//g ) .