[" Tangents are drawn to the ellipse "(x^(2))/(9)+(y^(2))/(5)=1" at the ends of latus-rectum.The area of the quadrilateral so "],[" umed is "]

Tangents are drawn to the ellipse x^(2)/9+y^(2)/5=1 at the ends of latus rectum. The area of the quadrilateral formed, is

Tangents are drawn to the ellipse (x^2)/(9)+(y^2)/(5)=1 at the ends of both latusrectum. The area of the quadrilateral so formed is

Tangents are drawn to the ellipse (x^(2))/(9)+(y^(2))/(5)=1 at the end of latus rectum. Find the area of quadrilateral so formed

Tangents are drawn to the ellipse x^2/9+y^2/5 = 1 at the end of latus rectum. Find the area of quadrilateral so formed

Tangents are drawn to the ellipse x^2/9+y^2/5 = 1 at the end of latus rectum. Find the area of quadrilateral so formed

For the ellipse (x^(2))/(4) + (y^(2))/(3) = 1 , the ends of the two latus rectum are the four points

For the ellipse (x^(2))/(4) + (y^(2))/(3) = 1 , the ends of the two latus rectum are the four points

Tangents are drawn to the ellipse 5x^(2)+ 9y^(2)=45 at the four ends of two latera recta. The area (in square unit) of the quadrilateral so formed is-