A time varying force `F=6t-2t^(2)N`, at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at `t=0` the force `F=0`. Now answer the following:
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A time varying force F=6t-2t^(2)N , at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at t=0 the force F=0 . Now answer the following: Find the duration for which the force acts on the body.

A time varying force F=6t-2t^(2)N , at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at t=0 the force F=0 . Now answer the following: Find the duration for which the force acts on the body.

A time varying force F=6t-2t^(2)N , at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at t=0 the force F=0 . Now answer the following: Find the time when the velocity attained by the body is maximum.

A time varying force F=6t-2t^(2)N , at t=0 starts acting on a body of mass 2kg initially at rest, where t is in second. The force is withdrawn just at the instant when the body comes to rest again. We can see that at t=0 the force F=0 . Now answer the following: Find the time when the velocity attained by the body is maximum.

A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 "m s"^(-1) . Find the magnitude of the force.

A force given by the relation F = 8t, acts on a body of mass 2 kg, initially at rest. Find the work done by this force on the body during first 2 seconds of its motion

The displacement of a body of mass 2 kg varies with time t as S = t^(2) + 2t , where S is in seconds. The work done by all the forces acting on the body during the time interval t = 2s to t = 4s is

A force F= 2t^2 is applied to the cart of mass 10 Kg, initially at rest. The speed of the cart at t = 5 s is -