Using binomial theorem, expand `(x+1/y)^(11)dot`

Using binomial theorem, expand {(x+y)^5+(x-y)^5}dot and hence find the value of {(sqrt(2)+1)^5+(sqrt(2)-1)^5}dot

Using binomial theorem, expand [ ( x+y)^(5) + (x-y)^(5) ] and hence find the value of [ ( sqrt(3) + 1)^(5) - ( sqrt(3) - 1)^(5) ] .

Using binomial theorem expand (x^(2)+(1)/(x^(2)))^(4)

Using binomial theorem expand (x^(2)+(1)/(x^(2)))^(4)

Using binomial theorem,expand {(x+y)^(5)+(x-y)^(5)}* and hence find the value of {(sqrt(2)+1)^(5)+(sqrt(2)-1)^(5)}

Using binomial theorem expand (1+(x)/(2)-(2)/(x))^(4),x!=0

By using binomial theorem, expand: (1+x+x^2)^3

Using binomial theorem expand (sqrt(x/a)-sqrt(a/x))^6 .

Using binomial theorem expand (1+x/2-2/x)^4,\ x!=0.