A genotype AaBBCcDd can produce how many types of gametes?

Options

A. 4
B. 3
C. 8
D. 64

Answer

To determine how many types of gametes can be produced from the genotype AaBBCcDd, we can follow these steps:

### Step 1: Identify the heterozygous and homozygous alleles in the genotype.
- The given genotype is AaBBCcDd.
- Here, "A" and "a" are heterozygous (Aa), "B" and "B" are homozygous (BB), "C" and "c" are heterozygous (Cc), and "D" and "d" are heterozygous (Dd).

### Step 2: Count the number of heterozygous gene pairs.
- From the genotype:
- Aa (1 heterozygous)
- BB (0 heterozygous)
- Cc (1 heterozygous)
- Dd (1 heterozygous)

- Total heterozygous pairs = 1 (from Aa) + 0 (from BB) + 1 (from Cc) + 1 (from Dd) = 3 heterozygous pairs.

### Step 3: Use the formula to calculate the number of gametes.
- The formula to calculate the number of different gametes is \( 2^n \), where \( n \) is the number of heterozygous pairs.
- Here, \( n = 3 \).

### Step 4: Calculate the number of gametes.
- Plugging in the value of \( n \) into the formula:
\[ \text{Number of gametes} = 2^3 = 8 \]

### Conclusion:
- Therefore, the genotype AaBBCcDd can produce **8 different types of gametes**.

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